A) Thorium series
B) Fourier series
C) Actinium series
D) Neptunium series
Correct Answer: D
Solution :
Since, remainder is one when atomic mass of the given end product is divided by 4, it belongs to \[(4n+1)\] or neptunium series or in other words, it is the end product of neptunium series.You need to login to perform this action.
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