A) \[-271\,kJ\]
B) \[1.403J\]
C) \[-135kJ\]
D) \[-115kJ\]
Correct Answer: A
Solution :
\[2{{e}^{-}}+2VO_{2}^{+}+4{{H}^{+}}\xrightarrow{{}}2V{{O}^{2+}}+2{{H}_{2}}O;\] \[\Delta {{E}^{o}}=1.0V\] ??.(i) \[Cd\xrightarrow{{}}C{{d}^{2+}}+2{{e}^{-}}{{;}^{*}}\Delta {{E}^{o}}=+0.40V\] ?(ii) On adding Eq (i) and (ii), we get \[2VO_{2}^{+}+4{{H}^{+}}+Cd\to 2V{{O}^{2+}}+2{{H}_{2}}O+C{{d}^{2+}};\] \[E_{cell}^{o}=1.0+0.40=1.40V\] \[\Delta {{G}^{o}}=-nFE_{cell}^{o}\] \[=-2\times 96500\times 1.4\] \[=-270200J\] \[=-271kJ\] Since in this Q. \[{{E}^{o}}\] values are not given, it is incorrect. These values are taken from reference books.You need to login to perform this action.
You will be redirected in
3 sec