A) \[C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}C{{H}_{2}}CHO\]
C) \[{{(C{{H}_{3}})}_{3}}CCHO\]
D) \[{{(C{{H}_{3}})}_{2}}CHCHO\]
Correct Answer: C
Solution :
The given reaction is Cannizaro reaction. It is given by only those aldehydes in which \[\alpha -H\] atom is not present. Hence, \[{{(C{{H}_{3}})}_{3}}C.CHO\] due to the absence of \[\alpha -H\] atom gives the Cannizaro reaction as \[2{{(C{{H}_{3}})}_{3}}C.CHO\xrightarrow{Conc.\,\,NaOH}{{(C{{H}_{3}})}_{3}}C.C{{H}_{2}}OH\]\[+{{(C{{H}_{3}})}_{3}}C.COONa\] \[{{(C{{H}_{3}})}_{2}}CHCHO\] also gives Cannizaro reaction, between in it \[\alpha -H\] atom is present.
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