A) \[B{{a}^{2+}}\]
B) \[C{{d}^{2+}}\]
C) \[C{{a}^{2+}}\]
D) \[S{{r}^{2+}}\]
Correct Answer: A
Solution :
Among the given ions, only \[B{{a}^{2+}}\] gives yellow precipitate of barium chromate, when treated with \[{{K}_{2}}Cr{{O}_{4}}\].\[B{{a}^{2+}}+{{K}_{2}}Cr{{O}_{4}}\xrightarrow{{}}\underset{yellow\,ppt.}{\mathop{BaCr{{O}_{4}}}}\,+2{{K}^{+}}\]
You need to login to perform this action.
You will be redirected in
3 sec
