A) \[\frac{1}{2}g\]
B) \[\frac{1}{4}g\]
C) \[\frac{1}{8}g\]
D) \[\frac{1}{16}g\]
Correct Answer: D
Solution :
\[t={{t}_{1/2}}\times n\] \[560=140\times n\] \[n=\frac{560}{140}=4\] \[N={{N}_{0}}\times {{\left( \frac{1}{2} \right)}^{n}}=1\times {{\left( \frac{1}{2} \right)}^{4}}\] \[=\frac{1}{16}g\]You need to login to perform this action.
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