A) 5
B) 6
C) 7
D) 8
Correct Answer: B
Solution :
The possible isomers of \[{{C}_{4}}{{H}_{8}}\] are as (i) \[\underset{1-butene}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,\] (ii) \[\underset{trans\,2-butene}{\mathop{C{{H}_{3}}\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\] (iii) \[\underset{cis\,2-butene}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\] (iv) \[\underset{2-methyl\,propane}{\mathop{C{{H}_{3}}\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\] (v) and (vi)You need to login to perform this action.
You will be redirected in
3 sec