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BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    If a spring extends by x on loading, thenenergy stored by the spring is (if T is thetension in the spring and k is the springconstant)

    A)  \[\left| a-b \right|\]                     

    B) \[a+b\]

    C) \[\sqrt{{{a}^{2}}+{{b}^{2}}}\]                                     

    D) \[\sqrt{{{a}^{2}}+{{b}^{2}}+2ab\,\cos \,x}\]

    Correct Answer: B

    Solution :

                    Energy stored by spring \[U=\frac{1}{2}k{{x}^{2}}\] But              \[T=kx\] So energy stored \[=\frac{1}{2}\frac{{{(kx)}^{2}}}{k}\]                                 \[=\frac{1}{2}\frac{{{T}^{2}}}{k}\]


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