A) the momentum of each particle remains constant separately
B) the magnitudes of momenta of bothbodies are same to each other
C) the mechanical energy of system remains constant
D) Both (a) and (b) are correct
Correct Answer: C
Solution :
Since no external force is present on the system so, conservation principle of momentum is applicable \[1.25\times {{10}^{6}}\] \[\frac{G}{19}\] (\[\frac{G}{20}\] \[E=16T-0.04{{T}^{2}}\mu V.\]) \[{{T}_{i}}\] From this point of view, it is clear that momenta of both particles are equal in magnitude put opposite in direction. Also, friction is absent. So total mechanical energy of system remains conserved.
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