A) \[2.0\times {{10}^{8}}N\]
B) \[2.0\times {{10}^{6}}N\]
C) \[v=\frac{W}{q}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[AT]}\]
D) \[v=\frac{W}{q}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[AT]}\]
Correct Answer: B
Solution :
Current at \[t=\infty ,{{i}_{t=\infty }}={{i}_{0}}\] Similarly \[{{i}_{t=1s}}={{i}_{0}}\left( 1-{{e}^{\frac{10}{5}\times 1}} \right)\] \[\therefore \] \[\frac{{{i}_{t=\infty }}}{{{i}_{t=1s}}}=\frac{{{i}_{0}}{{e}^{2}}}{{{i}_{0}}({{e}^{2}}-1)}=\frac{{{e}^{2}}}{{{e}^{2}}-1}\]
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