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BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    A 1 L vessel initially contains 2.0, 0.5 and 0.0 moles of \[{{N}_{3}}\], \[{{H}_{2}}\] and \[N{{H}_{3}}\] respectively. The system after attaining equilibrium has 0.2 mole of \[N{{H}_{3}}\]. The number of moles of \[{{H}_{2}}\] in the vessel at equilibrium is

    A)  \[0.3\]                                 

    B)  \[0.4\]

    C)  \[0.2\]                                 

    D)  \[1.8\]

    Correct Answer: C

    Solution :

                    \[\underset{(2.0-x)}{\mathop{\underset{2.0}{\mathop{{{N}_{2}}}}\,}}\,+\underset{(0.5-3x)}{\mathop{\underset{0.5}{\mathop{3{{H}_{2}}}}\,}}\,\underset{2x\,\,At\,\,equilibrium}{\mathop{\underset{0.0\,\,\,\,\,\,Initrially}{\mathop{2N{{H}_{3}}}}\,}}\,\] Given,  \[2x=0.2\]   \[x=0.1\] \[\therefore \]Number of moles of \[{{H}_{2}}\] at equilibrium                 \[=0.5-3\times 0.1\]                 \[=0.5-0.3=0.2\]


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