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BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    In double slit experiment, the distancebetween two slits is 0.6 mm and these areilluminated with light of wavelength 4800\[11.4\Omega ,15.5A\].The angular width of first dark fringe on thescreen distant 120 cm from slits will be

    A)  \[30.7\Omega ,6.5A\]                  

    B)  \[40.4\Omega ,5A\]

    C) \[50\Omega ,5A\]                           

    D)  \[{{R}_{1}}\]

    Correct Answer: A

    Solution :

                    Distance between two slits \[{{r}^{-5/2}}\] \[{{T}^{2}}\] \[{{r}^{3}}\] Angular width \[{{r}^{7/2}}\]                 \[{{r}^{5/2}}\]                 \[{{r}^{3/2}}\]


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