A) 1.5V
B) 3.85V
C) 2.35V
D) 15.4V
Correct Answer: A
Solution :
\[\left[ M{{L}^{2}}{{T}^{-2}}{{A}^{-2}} \right]\] \[\left[ M{{L}^{2}}{{T}^{-3}}{{A}^{-2}} \right]\] \[\frac{3}{2}m{{r}^{2}}\] Similarly, \[\frac{m{{r}^{2}}}{2}\] Now \[\frac{3}{8}m{{r}^{2}}\] and \[\frac{mx}{{{(m+1)}^{2}}}\] Hence, \[\frac{mx}{{{(m-1)}^{2}}}\] and \[\frac{{{(m+1)}^{2}}}{m}x\] Solving, we get \[\frac{{{(m-1)}^{2}}}{m}x\]You need to login to perform this action.
You will be redirected in
3 sec