A) 1 : 1
B) 1 : 2
C) 1 : 3
D) 1 : 4
Correct Answer: B
Solution :
\[\overset{0}{\mathop{A}}\,\] First case, \[8\times {{10}^{-4}}red\] Second case, \[6\times {{10}^{-4}}red\] Therefore, from Eqs. (i) and (ii), \[4\times {{10}^{-4}}red\] or \[16\times {{10}^{-4}}red\]You need to login to perform this action.
You will be redirected in
3 sec