A) 321 Hz
B) 298 Hz
C) 289 Hz
D) 280 Hz
Correct Answer: B
Solution :
The component of velocity of source along line joining \[{{v}_{s}}={{v}_{1}}\,\cos {{45}^{o}}=36\times \frac{1}{\sqrt{2}}km/h=5\sqrt{2}m/s\] Component of velocity of observer (second car) along line joining \[{{v}_{0}}={{v}_{2}}\,\cos {{45}^{o}}=72\times \frac{1}{\sqrt{2}}km/h\] \[=10\sqrt{2}m/s\] \[n=\frac{v+{{v}_{0}}}{v-{{v}_{s}}}n=\frac{330+10\sqrt{2}}{330-5\sqrt{2}}\times 280\] \[=\frac{344}{323}\times 280Hz=298Hz\]You need to login to perform this action.
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