A) \[\overset{0}{\mathop{A}}\,\]
B) \[8\times {{10}^{-4}}red\]
C) \[6\times {{10}^{-4}}red\]
D) \[4\times {{10}^{-4}}red\]
Correct Answer: C
Solution :
Number of electrons, n \[=\frac{6\times {{10}^{23}}}{63.5}\times 10\times \frac{1}{{{10}^{6}}}=\frac{6\times {{10}^{18}}}{63.5}\] \[q=\frac{6\times {{10}^{18}}\times 1.6\times {{10}^{-19}}}{63.5}C\] or \[q=1.5\times {{10}^{-2}}C\] \[F=\frac{9\times {{10}^{9}}\times 1.5\times {{10}^{-2}}\times 1.5\times 10h-2}{{{\left( \frac{10}{100} \right)}^{2}}}\] \[=2.0\times {{10}^{8}}N\]You need to login to perform this action.
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