A) ethanoic acid
B) methanoic acid
C) glyoxal
D) oxalic acid
Correct Answer: C
Solution :
\[Se{{O}_{2}}\] converts \[-C{{H}_{2}}\] group adjacent to the carbonyl group into group. \[\underset{acetaldehyde}{\mathop{\overset{HC{{H}_{2}}}{\mathop{\underset{CHO}{\mathop{|}}\,}}\,}}\,\xrightarrow{Se{{O}_{2}}}\underset{glyoxal}{\mathop{\overset{CHO}{\mathop{\underset{CHO}{\mathop{|}}\,}}\,}}\,\]You need to login to perform this action.
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