A) HF and \[{{O}_{2}}\]
B) HF and \[O{{F}_{2}}\]
C) HF and \[{{O}_{3}}\]
D) HF, \[{{O}_{2}}\] and \[{{O}_{3}}\]
Correct Answer: D
Solution :
Fluorine, when reacts with water gives both \[{{O}_{2}}\] and \[{{O}_{3}}\]. \[2{{H}_{2}}O+2{{F}_{2}}\xrightarrow{Cold}4HF+{{O}_{2}}\] \[3{{H}_{2}}O+3{{F}_{2}}\xrightarrow{Hot}6HF+{{O}_{3}}\]
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