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BVP Medical BVP Medical Solved Paper-2011

  • question_answer
    A car starts from rest and moves with uniform acceleration a on a straight road from time t= 0to t =T. After that, a constant deceleration brings it to rest. In this process, the average speed of the car will be

    A) \[\overset{0}{\mathop{A}}\,\]                 

    B) \[\overset{0}{\mathop{A}}\,\]

    C) \[\overset{0}{\mathop{A}}\,\]                 

    D)  \[\overset{0}{\mathop{A}}\,\]

    Correct Answer: B

    Solution :

                    The average speed of the car \[i\alpha \sqrt{\theta }\]              ??.(i) When car accelerates at constant rate a, then from second equation of motion                 \[\gamma \]                 \[\beta \]            (\[\alpha \]\[{{H}_{2}}\])           ??(ii) When car decelerates at same constant rate a, then again from second equation of motion \[{{O}_{2}}\]                      ?...(iii) From Eqs. (i), (ii) and (iii), we get Average speed \[F=i(i\times B)=0\]                 \[\tan \theta =\frac{V}{H}\]


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