A) 24
B) 36
C) 5
D) 30
Correct Answer: D
Solution :
Frequency \[{{v}_{H}}>{{v}_{N}}>{{v}_{o}}\] Also, v = number of holes x number of rev/s Given, \[{{v}_{o}}>,{{v}_{N}}\,=\,{{v}_{H}}\] \[{{v}_{o}}>,{{v}_{H}}\,=\,{{v}_{N}}\] \[{{v}_{N}}>,{{v}_{o}}\,=\,{{v}_{H}}\] \[=1.013\times {{10}^{5}}N/{{m}^{2}}\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\]You need to login to perform this action.
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