A) \[5.26\times {{10}^{3}}\]=0
B) \[({{R}_{e}}=6.37\times {{10}^{6}}m)\]
C) \[mg{{R}_{e}}\,.\]
D) \[{{R}_{e}}\]
Correct Answer: D
Solution :
Current lags the voltage if \[\frac{3}{2}M{{R}^{2}}\] \[\frac{5}{2}M{{R}^{2}}\] \[5.26\times {{10}^{3}}\] \[({{R}_{e}}=6.37\times {{10}^{6}}m)\]You need to login to perform this action.
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