A) 28.4 MeV
B) 20.8 MeV
C) 27-3 MeV
D) 14.2 MeV
Correct Answer: A
Solution :
In helium atom aHe4 (N = 2, P = 2) Mass defect \[1\frac{1}{2}mg{{R}_{e}}\]= (mass of 2 proton + mass of 2 neutrons) =mass of \[-\frac{1}{2}mg{{R}_{e}}\]-particle \[{{\alpha }_{1\,}}and\,{{\beta }_{2}}\] \[{{Y}_{1\,}}and\,{{Y}_{2}}\] Binding energy \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\frac{2}{3}\] \[\frac{{{Y}_{1}}}{{{Y}_{2}}}\]You need to login to perform this action.
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