A) d = 10
B) \[{{10}^{-5}}\]
C) d = 40
D) d = 20
Correct Answer: D
Solution :
For thin lens \[{{R}_{e}}\] \[{{R}_{e}}\] \[-2mg{{R}_{e}}\] Rays coming parallel to the axis will converge at the focus. \[2mg{{R}_{e}}\] \[1\frac{1}{2}mg{{R}_{e}}\] \[-\frac{1}{2}mg{{R}_{e}}\] \[{{\alpha }_{1\,}}and\,{{\beta }_{2}}\]\[{{Y}_{1\,}}and\,{{Y}_{2}}\] \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\frac{2}{3}\]
You need to login to perform this action.
You will be redirected in
3 sec
