A) \[_{7}{{N}^{14}}{{(p,\alpha )}_{8}}{{O}^{17}}\]
B) \[_{8}{{O}^{17}}{{(\alpha ,p)}_{7}}{{N}^{14}}\]
C) \[_{7}{{O}^{14}}{{(\alpha ,p)}_{8}}{{O}^{17}}\]
D) \[_{8}{{O}^{17}}{{(p,\alpha )}_{7}}{{N}^{14}}\]
Correct Answer: C
Solution :
\[\underset{\alpha -particle}{\mathop{_{2}H{{e}^{4}}}}\,{{+}_{7}}{{N}^{14}}{{\xrightarrow{{}}}_{8}}{{O}^{17}}+\underset{proton}{\mathop{_{1}{{H}^{1}}}}\,\] This is a \[\alpha \], p type nuclear reaction and is represented as \[_{7}{{N}^{14}}\,{{(\alpha ,p)}_{8}}{{O}^{17}}\].
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