A) 70km
B) 120km
C) 170 km
D) 220 km
Correct Answer: C
Solution :
Here \[-\frac{1}{2}mg{{R}_{e}}\] Centripetal acceleration \[{{\alpha }_{1\,}}and\,{{\beta }_{2}}\] \[{{Y}_{1\,}}and\,{{Y}_{2}}\] \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\frac{2}{3}\] \[\frac{{{Y}_{1}}}{{{Y}_{2}}}\] \[{{v}_{H}},{{v}_{N}}\,and\,{{v}_{o}}\] \[{{v}_{H}}>{{v}_{N}}>{{v}_{o}}\] \[{{v}_{o}}>,{{v}_{N}}\,=\,{{v}_{H}}\] \[{{v}_{o}}>,{{v}_{H}}\,=\,{{v}_{N}}\]Height of satellites orbit above the earths surface \[{{v}_{N}}>,{{v}_{o}}\,=\,{{v}_{H}}\] \[=1.013\times {{10}^{5}}N/{{m}^{2}}\] \[\overset{0}{\mathop{A}}\,\]You need to login to perform this action.
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