A) \[La\]
B) \[Nd\]
C) \[Ce\]
D) \[Eu\]
Correct Answer: D
Solution :
Outer electronic configuration of Eu (Z = 63) is \[4{{f}^{7}}\,\,6{{s}^{2}}\]. As the outer electronic configuration of \[E{{u}^{2+}}\]is \[4{{f}^{2}}\], making it stable and all lanthanides show \[+3\] oxidation state. Thus, Eu exhibits \[+2\] and \[+3\] oxidation states.You need to login to perform this action.
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