A) (i), (iii) and (iv)
B) (ii), (iii) only
C) (ii), (iii) and (iv)
D) All of these
Correct Answer: C
Solution :
Fluorine does not form oxyacids as it is most electronegative element of the Periodic Table. \[2{{F}_{2}}+4NaOH\xrightarrow{Hot}4NaF+{{O}_{2}}+2{{H}_{2}}O\] \[{{F}_{2}}+2NaOH\xrightarrow{Cold}2NaF+\frac{1}{2}{{O}_{2}}+{{H}_{2}}O\] \[\therefore \] \[{{F}_{2}}\] reacts with hot \[NaOH\] to give \[NaF\], \[{{O}_{2}}\] and \[{{H}_{2}}O\].You need to login to perform this action.
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