A) the axial p-p orbital overlap
B) the sideways p-p orbital overlap
C) the 5-5 orbital overlap
D) the 5-p orbital overlap
Correct Answer: A
Solution :
The electronic configuration of fluorine atom is \[_{9}F=1{{s}^{2}},2{{s}^{2}},2{{p}^{5}}\]
The \[{{p}_{z}}\] orbitals of two fluorine atoms overlap axially to form a fluorine molecule.
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