A) two
B) one
C) zero
D) half
Correct Answer: D
Solution :
\[A\xrightarrow{{}}E\] \[\frac{dx}{dt}=k{{[A]}^{n}}\] \[\frac{d{{x}^{1}}}{dt}=k{{[4.A]}^{n}}=2\left( \frac{dx}{dt} \right)\] \[\frac{d{{x}^{1}}/dt}{dx/dt}={{\left( \frac{4}{1} \right)}^{n}}\] \[2={{\left( \frac{4}{1} \right)}^{n}}\] \[n=\frac{1}{2}\]You need to login to perform this action.
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