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BVP Medical BVP Medical Solved Paper-2012

  • question_answer
    If \[\frac{{{r}_{B}}}{{{r}_{A}}}\] = surface charge density, E = electric permittivity, the dimensions of \[\frac{{{r}_{A}}}{{{r}_{B}}}\] are same as

    A)  electric force

    B)  electric field intensity

    C)  pressure

    D)  electric charge

    Correct Answer: A

    Solution :

                    The electric field due to conducting infinite sheet is\[E=\frac{\sigma }{\varepsilon }\]


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