question_answer

For circuit the equivalent capacitance between P and Q is

A)  \[\frac{r_{A}^{2}}{R_{B}^{2}}\]                                

B)  \[\frac{R_{B}^{2}}{R_{A}^{2}}\]

C)  \[3m/{{s}^{2}}\]                                             

D)  \[-3m/{{s}^{2}}\]

Correct Answer: D

Solution :

                  \[\frac{1}{{{C}_{eq}}}=\frac{1}{3C}+\frac{1}{2C}+\frac{1}{C}=\frac{2+3+6}{6C}=\frac{11}{6C}\] \[{{C}_{eq}}=\frac{6C}{11}\]