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BVP Medical BVP Medical Solved Paper-2012

  • question_answer
    For the chemical reaction \[A\xrightarrow{{}}E\], it is found that the rate of the reaction doubles when the concentration of A is increased four times. The order in terms of A for this reaction is

    A)  two                                      

    B)  one

    C)  zero                                     

    D)  half

    Correct Answer: D

    Solution :

                    \[A\xrightarrow{{}}E\] \[\frac{dx}{dt}=k{{[A]}^{n}}\] \[\frac{d{{x}^{1}}}{dt}=k{{[4.A]}^{n}}=2\left( \frac{dx}{dt} \right)\] \[\frac{d{{x}^{1}}/dt}{dx/dt}={{\left( \frac{4}{1} \right)}^{n}}\] \[2={{\left( \frac{4}{1} \right)}^{n}}\] \[n=\frac{1}{2}\]


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