A) higher pH of blood
B) partial pressure of \[{{O}_{2}}\] and \[C{{O}_{2}}\]
C) low temperature in lungs and higher temperature in diffusion
D) All of the above
Correct Answer: D
Solution :
Blood play an important role in transport of oxygen and \[C{{O}_{2}}\]. Haemoglobin , respiratory pigment present in RBCs combine with \[{{O}_{2}}\] to form oxyhaemoglobin \[H{{b}_{4}}+4{{O}_{2}}\xrightarrow[Tissue]{Lungs}H{{b}_{4}}{{O}_{8}}\] Above reaction is reversible. The oxyhaemoglobin formed reaches the place of diffusion. The release of oxygen from the blood to tissues is important in the same way as the rapid absorption by the blood during its passage through the lungs. \[H{{b}_{4}}{{O}_{3}}\xrightarrow{{}}H{{b}_{4}}{{O}_{2}}\] The reduced haemoglobin is again transported via blood to lungs and the cycle is repeated contineously. The dissociation (reduction) of oxyhaemoglobin is facilitated by higher pH of blood (7.4) partial pressure of and \[C{{O}_{2}}\] 40 mm Hg and 46 mm Hg respectively and low temperature in lungs and higher temperature in tissues (diffusing sites).
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