A) \[2.80\times {{10}^{5}}\]
B) \[{{10}^{4}}\Omega \]
C) \[10\Omega \]
D) \[4.62\times {{10}^{-2}}\]
Correct Answer: D
Solution :
\[E=nhv\] or \[ms\,\,\Delta T=nhv\] \[n=\frac{ms\,\,\Delta T}{hv}\] \[=\frac{400\times 4.2\times (40-20)}{6.625\times {{10}^{-34}}\times 3\times {{10}^{5}}}\] \[=1.69\times {{10}^{29}}\] Photons \[=\frac{1.69\times {{10}^{29}}}{6.023\times {{10}^{23}}}\] \[=2.8\times {{10}^{5}}\]Photon/molYou need to login to perform this action.
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