A) \[6A\]
B) \[1.33\times {{10}^{-7}}kg\]
C) \[19.8\times {{10}^{-7}}kg\]
D) zero
Correct Answer: A
Solution :
\[e=\frac{d\phi }{dt}=\pi {{r}^{2}}\frac{dB}{dt}\] \[E(2\pi r)=\pi {{r}^{2}}\frac{dB}{dt}\] \[E=\frac{1}{2}r\frac{dB}{dt}\] \[dF=\lambda dsE\] \[d\tau =\lambda dsE\] \[d\tau =r\lambda dsE\] \[\tau =\lambda rE\int{ds}=\lambda E\,\,2\pi r\] \[=2\pi {{r}^{2}}\lambda \frac{1}{2}r\frac{dB}{dt}=\pi {{r}^{3}}\lambda \frac{dB}{dt}\]You need to login to perform this action.
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