A) \[0.835\]
B) \[0.756\]
C) \[0.638\]
D) \[0.930\]
Correct Answer: A
Solution :
\[{{M}_{2}}\](observe\[=\frac{1000\times 0.52\times 1.248}{100\times 0.0832}=78g\,\,mo{{l}^{-1}}\] \[i=\frac{208.34}{78}=2.67\] \[\underset{1-\alpha }{\mathop{\underset{1\,mol}{\mathop{BaC{{l}_{2}}}}\,}}\,\xrightarrow{{}}\underset{\alpha }{\mathop{\underset{0}{\mathop{B{{a}^{2+}}}}\,}}\,+\underset{\begin{smallmatrix} 0 \\ 2\alpha \end{smallmatrix}}{\mathop{2C{{l}^{-}}}}\,\] Number of total moles \[=1+2\alpha \] or \[i=1+2\alpha \] or \[\alpha =\frac{i-1}{2}=\frac{2.67-1}{2}=0.835\]You need to login to perform this action.
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