BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    A man weighs 80 kg the stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s. What would be the reading on the scale? \[400N\]

    A)  \[mg\,sin\,\theta \]                      

    B)  \[\frac{{{p}^{2}}{{t}^{2}}}{m}\]

    C)  zero                     

    D)  \[\frac{{{p}^{2}}{{t}^{2}}}{2m}\]

    Correct Answer: B

    Solution :

                    Mass of man m = 80 kg Acceleration of lift = 5 m/s When lift is moving upwards, the reading of weighing scale will be equal to R. The equation of motion gives                 \[1:5:3\] \[{{(Kg)}^{1/2}}\] \[{{(Kg)}^{-1/2}}\] \[{{(Kg)}^{2}}\]


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