A) \[\frac{pt}{2m}\]
B) \[\frac{2m{{L}^{2}}}{3}\]
C) \[\frac{m{{L}^{2}}}{12}\]
D) \[\frac{m{{L}^{2}}}{6}\]
Correct Answer: B
Solution :
We have \[2\] ?...(i) and \[2\sqrt{2}\] \[4\] \[\frac{1}{2}\] (F=P given) \[60m\] From Eq. (i). we get \[50m\]
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