A) \[1:5:3\]
B) \[{{(Kg)}^{1/2}}\]
C) \[{{(Kg)}^{-1/2}}\]
D) \[{{(Kg)}^{2}}\]
Correct Answer: C
Solution :
When the ball is released from the top of tower then ratio of distances covered by the ball in first, second and third second is \[0.36\times {{10}^{15}}Hz\] [because \[3.6\times {{10}^{15}}Hz\]] \[4.2\times {{10}^{15}}Hz\] Ratio of work done \[4.2\text{ }J/{{g}^{o}}C\]
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