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BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    Specific heat of water is \[{{40}^{o}}C\]. If light of frequency \[1.69\times {{10}^{29}}\] is used to heat 400 g of water from \[1.69\times {{10}^{28}}\] to \[2.80\times {{10}^{4}}\], the number of moles of photons needed will be

    A)  \[2.80\times {{10}^{5}}\]            

    B)  \[{{10}^{4}}\Omega \]

    C)  \[10\Omega \]                

    D)  \[4.62\times {{10}^{-2}}\]

    Correct Answer: D

    Solution :

                    \[E=nhv\] or   \[ms\,\,\Delta T=nhv\]                 \[n=\frac{ms\,\,\Delta T}{hv}\]                 \[=\frac{400\times 4.2\times (40-20)}{6.625\times {{10}^{-34}}\times 3\times {{10}^{5}}}\]                 \[=1.69\times {{10}^{29}}\]    Photons                 \[=\frac{1.69\times {{10}^{29}}}{6.023\times {{10}^{23}}}\]                 \[=2.8\times {{10}^{5}}\]Photon/mol


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