A) \[\frac{4{{v}^{2}}}{\sqrt{5}g}\]
B) \[(g=10m/{{s}^{2}})\]
C) \[800N\]
D) \[1200N\]
Correct Answer: A
Solution :
\[-\frac{\pi }{3}\] \[\frac{\pi }{6}\] \[-\frac{\pi }{6}\] From triangle we can say that \[\frac{\pi }{3}\] \[1:2:3\] Range of projectile \[1:4:9\] \[1:3:5\]You need to login to perform this action.
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