A) \[230\text{ }MeV\]
B) \[{{10}^{-10}}m,\]
C) \[4.2\times {{10}^{15}}\text{ }Hz\]
D) \[0.36\times {{10}^{15}}Hz\]
Correct Answer: A
Solution :
\[_{0}^{1}n+_{92}^{235}U\xrightarrow{{}}_{92}^{98}{{M}_{0}}+_{84}^{136}Xe+{{2}^{1}}{{n}_{0}}\] \[(1.0087+235.0439)\] \[=(97.9034+135.917+2.0174)\] \[\Delta m=0.2128\] Total energy released during a fission reaction \[=0.2128\times 931MeV\] \[=198Mev\]You need to login to perform this action.
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