A) \[Na,Li,B,Be\]
B) \[Li,Na,Be,B\]
C) \[Li,Be,B,Na\]
D) \[Na,Li,Be,B\]
Correct Answer: A
Solution :
\[Na-496kJ/mo{{l}^{-1}},\,\,Li\,\,520\,kJmo{{l}^{-1}},\]\[B-801\,\,kJmo{{l}^{-1}},\,Be-899\,kJmo{{l}^{-1}}\] On moving down the group, ionisation energy decreases with increase in size while in a period it increases with decrease in atomic sizes. \[l{{E}_{1}}\] of Be is greater than B because of stable configuration of Be i.e., \[1{{s}^{2}}2{{s}^{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
