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BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    The  maximum number of possible interference maxima from slit-separation equal to twice the wavelength in Youngs double-slit experiment is

    A)  infinite                                

    B)  five   

    C)  three                                   

    D)  zero

    Correct Answer: B

    Solution :

                    For possible interference maxima on the screen, the condition is \[{{40}^{o}}C\] Given,                 \[{{80}^{o}}C\]                 \[{{100}^{o}}C\]                 \[{{20}^{o}}C\]                     ?..(i)   The maximum value of sin 9 is 1, hence                 \[R=8.31Jmo{{l}^{-1}}{{K}^{-1}}\] Thus, Eq. (i) must be satisfied by 5 integer values i.e.,         \[996\text{ }J\]


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