A) soda lime
B) \[NaOH\]
C) \[KMn{{O}_{4}}\]
D) \[N{{a}_{2}}C{{O}_{3}}\]
Correct Answer: A
Solution :
\[\underset{Sod.\,benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COONa}}\,\xrightarrow{Sodaime.\,\Delta }\underset{Benzene}{\mathop{{{C}_{6}}{{H}_{6}}}}\,+N{{a}_{2}}C{{O}_{3}}\]
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