A) \[Cs-Cl\]
B) \[CsCl\]
C) \[Cl\]
D) \[62.92%\]
Correct Answer: B
Solution :
Given, \[90.71kJ\] and \[122.55kJ\] \[H{{g}^{2+}}+2C{{l}^{-}}HgC{{l}_{2}},\] \[k=1.65\times {{10}^{3}}\] and \[H{{g}^{2+}}\] Since, \[2.0m\text{ }mol\]for \[H{{g}^{2+}}\] for \[C{{l}^{-}}\] \[825\times {{10}^{14}}M\] Redox changes: At anode \[1.65\times {{10}^{13}}M\] At cathode \[2.87\times {{10}^{6}}M\] Overall reaction \[6.72\times {{10}^{6}}M\] Hence, \[{{K}_{f}}\] \[-{{0.360}^{o}}C\] or \[-{{0.260}^{o}}C\] and \[2.87\times {{10}^{6}}M\] \[672\times {{10}^{6}}M\] \[AB\] \[{{\log }_{e}}\,\,K=4.0-\frac{2000}{T}\]You need to login to perform this action.
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