BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    A motor cycle racer takes a round with speed of 20m/s in a curvature of radius of R=40 m, then the leaning angle of motor cycle for safe turn is(\[62V,\,\,2\Omega \])

    A)  \[63V,\,\,1\Omega \]                   

    B)  \[61V,\,\,1\Omega \]

    C)  \[64V,\,\,2\Omega \]                                   

    D)  \[15min\]

    Correct Answer: C

    Solution :

                    A motor cyclist provides himself, the necessary centripetal force by leaning inward on a horizontal track, which going round a curve. For a safe turn cyclist should bend through an angle \[\theta ={{\tan }^{-1}}\left[ \frac{{{v}^{2}}}{2g} \right]\] \[={{\tan }^{-1}}\left[ \frac{{{(20)}^{2}}}{40\times 10} \right]\] \[={{\tan }^{-1}}(1)\left[ \frac{{{(20)}^{2}}}{240\times 10} \right]\] \[={{\tan }^{-1}}(1)={{45}^{o}}\]


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