BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    Three masses of 2 kg, 4 kg and 4 kg are placed at the three points (1, 0, 0), (1, 1, 0) and (0, 1, 0) respectively. The position vector of its centre of mass is

    A)  \[\frac{\omega M}{M+m}\]

    B)  \[\frac{\omega (M-2M)}{M+2m}\]

    C)  \[\frac{\omega (M+2M)}{M}\]

    D)  \[\frac{\omega M}{M+2m}\]

    Correct Answer: A

    Solution :

                     \[{{v}_{cm}}=\frac{{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{2\times (\hat{i})+4(\hat{i}+\hat{j})+4(\hat{j})}{2+4+4}\] \[=\frac{3}{5}\hat{i}+\frac{4}{5}\hat{j}\]


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