A) \[30\mu A\]
B) \[90\mu A\]
C) \[4mA\]
D) \[2mA\]
Correct Answer: B
Solution :
\[{{R}_{t}}={{R}_{0}}(1+\alpha t)\] \[\alpha =0.00125\] \[1\Omega ={{R}_{0}}(1+0.00125\times 27)\] ??..(i) \[2\Omega ={{R}_{0}}(1+0.00125\times t)\] ???(ii) From Eqs. (i) and (ii), we get \[\frac{1}{2}=\frac{1+\frac{125}{10000}\times 27}{1+\frac{125}{100000}\times t}=\frac{827}{800t}\] \[=800t=1654\] \[t={{854}^{o}}C\] \[T=(854+273)K\] \[=1127K\]
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