A) \[{{10}^{29}}\]
B) \[250\times {{10}^{-3}}m/s\]
C) \[25\times {{10}^{-3}}m/s\]
D) \[2.50\times {{10}^{-3}}m/s\]
Correct Answer: C
Solution :
\[\frac{hv}{4}\] \[\frac{hv}{3}\] \[\frac{hv}{2}\] \[\frac{2hv}{3}\] According to work-energy theorem, change in kinetic energy is equal to work done \[30\mu A\] Thus, power delivered to the particle \[90\mu A\]You need to login to perform this action.
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