A) monoatomic
B) diatomic
C) polyatomic
D) mixture of diatomic and polyatomic molecules
Correct Answer: A
Solution :
\[\frac{{{C}_{P}}}{{{C}_{V}}}=\gamma \] Also \[{{C}_{P}}-{{C}_{V}}=R\] \[\frac{{{C}_{P}}}{{{C}_{V}}}-1=\frac{R}{{{C}_{V}}}=0.67\] \[\frac{{{C}_{P}}}{{{C}_{V}}}=\gamma =1+0.67\] \[=1.67=\frac{5}{3}\] (For monoatomic gas)You need to login to perform this action.
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